Single Number
Problem
https://leetcode.com/problems/single-number/
Given a non-empty array of integers nums, every element appears
twice except for one. Find that single one.
You must implement a solution with a linear runtime complexity and use only constant extra space.
Example 1:
Input: nums = [2,2,1]
Output: 1
Example 2:
Input: nums = [4,1,2,1,2]
Output: 4
Example 3:
Input: nums = [1]
Output: 1
Constraints:
1 <= nums.length <= 3 * 104-3 * 104<= nums[i] <= 3 * 104Each element in the array appears twice except for one element which appears only once.
Pattern
Bit Manipulation
Approaches
Code
def singleNumber(nums: list[int]) -> int:
"""Return the element that appears only once."""
result = 0
for num in nums:
result ^= num
return result
Test
>>> from single_number__xor import singleNumber
>>> singleNumber([2, 2, 1])
1
>>> singleNumber([4, 1, 2, 1, 2])
4
>>> singleNumber([1])
1
- single_number__xor.singleNumber(nums: list[int]) int
Return the element that appears only once.