Longest Substring Without Repeating Characters

Problem

https://leetcode.com/problems/longest-substring-without-repeating-characters/

Given a string s, find the length of the longest substring without duplicate characters.

Example 1:

Input: s = "abcabcbb"
Output: 3
Explanation: The answer is "abc", with the length of 3. Note that "bca" and "cab" are also correct answers.

Example 2:

Input: s = "bbbbb"
Output: 1
Explanation: The answer is "b", with the length of 1.

Example 3:

Input: s = "pwwkew"
Output: 3
Explanation: The answer is "wke", with the length of 3.
Notice that the answer must be a substring, "pwke" is a subsequence and not a substring.

Constraints:

  • 0 <= s.length <= 5 * 10:sup:`4`

  • s consists of English letters, digits, symbols and spaces.

Pattern

Hash Table, String, Sliding Window

Solution

The longest substring can start from any position in the string. So, we must iterate through each position in the entire string. For each position, we look right until we find a duplicate character. At each iteration, if the current substring is longer than the longest, we update the length of the longest substring. Once we find a duplicate character, reset the seen characters.

Code

def lengthOfLongestSubstring(s: str) -> int:
    """Finds the length of the longest substring without repeating characters.
    """
    longest_len = 0
    for i in range(len(s)):
        j = i
        seen_chars = set()
        curr_len = 0
        while j < len(s):
            char = s[j]
            if char in seen_chars:
                break
            else:
                curr_len += 1
                seen_chars.add(char)
                j += 1

            longest_len = max(longest_len, curr_len)

    return longest_len

Test

>>> from longest_substring_without_repeating_characters__approach_1 import lengthOfLongestSubstring
>>> lengthOfLongestSubstring('abcabcbb')
3
>>> lengthOfLongestSubstring('bbbbb')
1
>>> lengthOfLongestSubstring('pwwkew')
3

Complexity

\(n\) is the length of the input string
Time: \(O(n^2)\) — attempt to build substring starting at each character
Auxiliary Space: \(O(n)\) — substring storage
longest_substring_without_repeating_characters__approach_1.lengthOfLongestSubstring(s: str) int

Finds the length of the longest substring without repeating characters.