Intersection Of Two Arrays Ii
Problem
https://leetcode.com/problems/intersection-of-two-arrays-ii/
Given two integer arrays nums1 and nums2, return an array of
their intersection. Each element in the result must appear as many
times as it shows in both arrays and you may return the result in any
order.
Example 1:
Input: nums1 = [1,2,2,1], nums2 = [2,2]
Output: [2,2]
Example 2:
Input: nums1 = [4,9,5], nums2 = [9,4,9,8,4]
Output: [4,9]
Explanation: [9,4] is also accepted.
Constraints:
1 <= nums1.length, nums2.length <= 10000 <= nums1[i], nums2[i] <= 1000
Follow up:
What if the given array is already sorted? How would you optimize your algorithm?
What if
nums1’s size is small compared tonums2’s size? Which algorithm is better?What if elements of
nums2are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?
Pattern
Array, Hash Table, Two Pointers, Binary Search, Sorting
Approaches
Explanation
Count the number of times each number appears in each array in 2
dictionaries counter1 and counter2. For each key in
counter1 and counter2, add key repeated
min(counter1[key], counter2[key])
times to the intersection list.
Code
from collections import Counter
def intersect(nums1: list[int], nums2: list[int]) -> list[int]:
"""Finds the elements in common between 2 arrays."""
counter1 = Counter(nums1)
counter2 = Counter(nums2)
intersection = []
for key, val in counter1.items():
if key in counter2:
repeat = min(val, counter2[key])
intersection.extend(repeat * [key])
return intersection
Test
>>> from intersection_of_two_arrays_ii__hash_map import intersect
>>> intersect([1,2,2,1], [2,2])
[2, 2]
>>> intersect([4,9,5], [9,4,9,8,4])
[4, 9]
Complexity
\(m\) is the length of nums1 and \(n\) is the length of nums2
Measure |
Complexity |
Notes |
|---|---|---|
Time |
\(O(m + n)\) |
count each array and then iterate through the keys of the smaller dictionary |
Auxiliary Space |
\(O(m + n)\) |
2 dictionaries store at most \(m\) and \(n\) key-value pairs respectively |
- intersection_of_two_arrays_ii__hash_map.intersect(nums1: list[int], nums2: list[int]) list[int]
Finds the elements in common between 2 arrays.